LMO

Table. 5.

An example of spiking-recovery study

Sample Test Rep #1 Rep #2 Mean Diff %Recovery Mean %Recovery
A Spiked with pure solvent 10.7 11.3 11.0 1.90 95.0 93.3
Spiked with spiking solution 12.7 13.1 12.9
B Spiked with pure solvent 10.8 10.9 10.9 1.75 87.5
Spiked with spiking solution 12.5 12.7 12.6
C Spiked with pure solvent 11.1 11.4 11.3 1.95 97.5
Spiked with spiking solution 13.1 13.3 13.2

This example was extracted from the 1st edition of ‘Practical Handbook of Laboratory Medicine’ [16].

For example, when 0.05 mL of a 40-mg/dL spiking solution is added to 0.95 mL of serum, the added concentration of analyte is 40∙(0.05/1)=2 mg/dL.

Perform multiple measurements on each test sample (samples spiked with pure solvent, and samples spiked with spiking solution), and calculate the difference between the sample spiked with spiking solution and the sample spiked with pure solvent. In this example, the %recovery=100∙(calculated difference) / (expected difference), and the expected difference is 2 mg/dL. Then, compare the mean %recovery to the target %recovery.

Lab Med Online 2024;14:163~175 https://doi.org/10.47429/lmo.2024.14.3.163
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